Hello! I'm here to help you with the Çℎḙḡḡ link you provided. In the link you shared, the question pertains to a fluid system with a mass of 0.311 slug, a density of 30 lb/ft^3, and a specific gravity of 3.19. The task is to find the specific weight of the fluid.
To solve this problem, we need to understand the concept of specific weight. Specific weight is defined as the weight per unit volume of a substance. It is calculated using the formula:
\[ \text{Specific Weight} = \text{Density} \times g \]
Where:
- Density is the mass per unit volume of the substance (given as 30 lb/ft^3 in this case).
- \( g \) is the acceleration due to gravity, which is approximately 32.2 ft/s^2.
Given that the specific gravity is 3.19, we can find the density of the fluid using the relation between specific gravity and density:
\[ \text{Specific Gravity} = \frac{\text{Density of Substance}}{\text{Density of Water}} \]
Let's solve for the density of the fluid first:
\[ 3.19 = \frac{\text{Density of Substance}}{62.4} \]
\[ \text{Density of Substance} = 3.19 \times 62.4 \approx 199.656 \, \text{lb/ft}^3 \]
Now, we can calculate the specific weight of the fluid:
\[ \text{Specific Weight} = 199.656 \times 32.2 \approx 6430.0432 \, \text{lb/ft}^3 \]
Therefore, the specific weight of the fluid in the given system is approximately 6430.0432 lb/ft^3.
I hope this helps! Let me know if you need further clarification.
PH