🎓 Academic Çℎḙḡḡ Unlock

[SomeDay09]

Sa may mabubuting puso jan pa unlock nman nito mga lods

Çℎḙḡḡ Links:
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[S U P E R I O R]

Dito Kapatid. láρág mo yan!

https://phcorner.org/threads/free-Çℎḙḡḡ-unlock-just-leave-a-link.1095068/

 

[Cutthroat]

Are you from UC?

 

[SomeDay09]

Yes. Thank you nga pala dito

 

[Cutthroat]

andon kaba sa #forbidden# channel sa UC? my same question kasi ka don hihi

 

[SomeDay09]

Wala po

 

[Cutthroat]

[XX='SomeDay09, c: 1216247, m: 1725058'][/XX] nag pm ko

 

[jonbinsdesu]

Are you from UC?

View attachment 1432919View attachment 1432927View attachment 1432928

Sir baka pwede po mag pa unlock?

https://www.Çℎḙḡḡ.com/homework-help...ind-degree-vertices-g-order-size-gr-q78124614

 

[Cutthroat]

1.)

Vertex set of G = { v1, v2, v3, v4, v5, v6, v7, v8 }

Edge set of G = { (v1,v2), (v1, v5), (v2, v3), (v2, v4), (v2, v5), (v3, v5), (v3, v4), (v4, v5), (v4, v6), (v5, v6), (v6, v7), (v7, v8)}

(remember the edges are undirected, hence (v1,v2) doesn't mean an edge from v1 to v2 but it just means that an edge between v1 and v2

The degree of each vertex :

v1 - 2 ,

v2 - 4 ,

v3 - 3 ,

v4 - 4 ,

v5 - 5,

v6 - 3,

v7 - 2,

v8 - 1

The order of graph G = 8

The size of graph G = 12

2.) Graph will be -

If person 1 is John, then John knows 3 persons

 

[zamm]

https://www.Çℎḙḡḡ.com/homework-help...ressure-steam-pipe-joints-****-weld-q75076964

pa unlock nmn po, need lang po. thanks in advance po.

 

[Cutthroat]

 

[zamm]

https://www.Çℎḙḡḡ.com/homework-help...-lb-h-9070-kg-h-20-percent-solution-q33499026

baka po pwede pa po pa unlock ulit.. salamat po ulit.,

 

[bucan]

https://www.Çℎḙḡḡ.com/homework-help...pter-2-problem-6pe-solution-9781285982809-exc
idol need ko ngayon baka naman po

 

[Cutthroat]

Feed = 9070 kg/h

NaOH in Feed = 0.2

NaOH in Product = 0.5

Steam Pressure = 1.37 atm = 138.815 kPa

Vap Pressure = 100 mmHg = 13.33 kPa

U = 1400 W/m2°C

Feed Temperature, Tf = 37.8°C

Overall Material Balance, F = L + V = 9070 = L+V ....(1)

Component balance on NaOH, Fxf = Lxl

9070*0.2 = L *0.5

L = 3628 kg/h
V = 5442 kg/h (from Eq (1))

To determin T1 = Tsat + BPR of 50% concentrated NaOH product, first we obtain Tsat of Pure water from Steam Table. At 13.33 kPa, Tsat = 52°C

From Duhring chart for Tsat = 41.06 & 50% NaOH, boiling point of the solution is, T1 = 93.33°C

BPR = T1-Tsat = 93.33-52 = 41.33°C

From enthalpy concentration chart for superheated steam, Tf = 37.8 °C & xf = 0.2, then hf = 150 kJ/kg

T1 = 93.33°C & Xl = 0.5 then hf = 545 kJ/kg

For saturated steam at 1.37 atm from steam table we get,

Ts = 109.32°C and

= 2231.9 kJ/kg

To get Hv for superheated vapor, first we obtain the enthalpy at T sat = 52°C & P1 = 13.33 kPa, get Hsat = 2594.04kJ/kg

Then using heat capacity of 1.884 kJ/kg K of superheated steam, Hv = Hsat + Cp BPR

Hv = 2594.04 + 1.884 *41.33 = 2671.9 kJ/kg

Substituting in heat balance equation and solving for S,

Fhf + S lambda = Lhl + VHv

9070*150 + S*2231.9 = 3628*545 + 5442*2671.9

S = 6791.196 kg steam / hr

q = S lambda

q = 6791.18*2231.9*1000/3600 = 4210344 W

q = UA(Ts-T1)

A = 4210344 /(1400* (109.32-93.33)

A = 188 m2

Economy = 5442/6791.196

Economy = 0.8

 

[Cutthroat]

here

 

[zamm]

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pa unlock po ulit lodi.. super need lang po.. Thanks in advance po ulit.

 

[onse]

paunlock po scribed kung okay lang po salamat po

 

[electromagnus06]

Boss, patulong naman po huhuhu badly needed lang po talaga ,pasensya na po

https://www.Çℎḙḡḡ.com/homework-help...ejek-0-j-k-vector-product-v1-x-v2-r-q52535890

 

[onse]

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