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Given that

Specific gravity of light mineral = 0.85

Specific gravity of polysorbate =1.08

Therefore

Density of light mineral = specific gravity * density of water

= 0.85 *1.0 g/ ml

= 0.85 g/ ml

And density of poly sorbate = 1.08 *1 g/ ml

= 1.08 g/ ml

And density = mass / volume

So , volume = mass/ density

=light mineral : volume = 10 g/ 0.85 g/ mll

= 11.76 ml

poly sorbate: volume = 1 g/ 1.08 g/ ml

= 0.93 ml
 
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The IKEA way can be either be a positive or a negative business model. It depends on the overall implementation process and the effect it has on the customers. If the structural change helps attract the customers' attention and cater to both said and unsaid wants, then it may turn to have an advantage. In such a case, the customer may be intrigued to go through the store. On the other hand, if the store doesn't manage to satisfy the needs of the customers, the latter may soon loose interest as it would be time consuming and very tiresome process to shop in the store. The store must design the layout to suffice the needs of all categories of customers - customers who are in hurry as well as customers who are at leisure
 
IKEA's worldwide policies walk into an IKEA store anywhere in the world, and could identify it immediately. Strategy equality is extensive. The store type sells the same lane variety of reasonably priced home furniture, kitchens, accessories, and food. Most of the goods are immediately identifiable as IKEA products, with their clean yet attractive appearance and efficient design.

IKEA's objective is upwardly mobile consumers in their 20's and 30's who are looking for reasonably priced but fashionable furniture and accessories. Its stores are deliberate to guide customers through a network of shop and present that confirm how IKEA products can be used to provide each room in the residence as a method to give confidence desire purchase.


Originally, IKEA's worldwide strategy was to offer the matching modern, European mode goods in its global stores that made it fashionable in Western Europe.


Today, the business has enthused toward a more restricted policy, tailoring its goods and showrooms to concentrate on variation in society and standard of living among its customers.

IKEA's dealer is a significant relation in the company's mission to offer comparatively identical, excellence, low-priced products to its marketplace.

Customers almost certainly identify that for IKEA shop a long-term, trust affiliation with suppliers is fundamental.

IKEA relies on its dealer to scratch expenses so that its model can be manufactured at a sensible cost.

Version to limited experience and partiality was the consequence of a tender learning practice for IKEA. While the businesses initially come into the United States in the late 1980's, it consideration that purchaser would gather to its provisions the similar approach that they had in Western Europe. Initial they do, but they didn't buy as expected, and transaction cut down small of expectations.


Earlier a new manufactured goods line is time demanding; IKEA requirements to work with its dealer approximately as however they are in-house, pretty than independent of the firm.
To accomplish this state, the dealers need to identify that IKEA will maintain its E×ρréšš and delight them well.
 
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1.
We know that,
E(X + c) = E(X) + c
SD(X + c) = SD(X)
where E and SD denotes the mean and standard deviation of X and c is a constant.
After adding 10 to every score,
Mean will be 75 + 10 = 85
Standard deviation will be same. SD = 5

We know that,
E(aX) = aE(X)
SD(aX) = aSD(X) where a is a constant.
When we double the scores,
Mean = 2 * 75 = 150
SD = 2 * 5 = 10

2.
The distribution is badly skewed with few extreme outliers - SIQ Range
Advanced statistical procedures - SD
Maximum Width - Range
Statistic that takes into account every score in the population - SD
Highest score in the distribution is more than 10 - SIQ range

3.
The true statements are
The variance will equal 1.
The distribution will be normal in shape

The mean will equal 0. So, the mean will equal 1, is a False Statement.
 
ABCDEFGHIJ
2a)
3Journal entries will be as follows:
4
5TransactionAccountDebitCredit
6a)Raw Materials Inventory210000
7Accounts Payable=E6
8
9b)Work in Progress Inventory178000
10Manufacturing overhead12000
11Raw Materials Inventory=E9+E10
12
13c)Work in Progress Inventory90000
14Manufacturing overhead110000
15Wage Payable=E13+E14
16
17d)Manufacturing overhead40000
18Depreciation Expense=E17
19
20e)Manufacturing overhead70000
21Accounts Payable=E20
22
23f)Work in process Inventory=F24
24Manufacturing Overhead=8*30000
25
26g)Finished Goods Inventory520000
27Work in Process Inventory=E26
28
29h)Accounts Receivable=F30
30Sales Revenue=480000*(1+25%)
31
32Cost of goods sold520000
33Finished Goods Inventory=E32
34
35b)
36
37Work in Process Inventory
38Beg. Bal.42000
39Direct Material=E9=E26Transferred to finished goods
40Direct Labor=E13
41Overhead=E23
42Balance=SUM(D38:D41)-SUM(E38:E41)
43
44Manufacturing Overhead
45Beg. Bal.0
46In-direct Material=E10=F24Overhead Allocated
47In-direct Labor=E14
48Depreciation=E17
49Other Overheads=E20
50Balance=SUM(E45:E49)-SUM(D45:D49)
51
 
#include<stdio.h>



void FIFO(char [],char [],int,int);

void lru(char [],char [],int,int);

void opt(char [],char [],int,int);



int main()

{

int ch,YN=1,i,l,f;

char F[10],s[25];

clrscr();

//system("clear");

printf("\n\n\tEnter the no of empty frames: ");

scanf("%d",&f);

printf("\n\n\tEnter the length of the string: ");

scanf("%d",&l);

printf("\n\n\tEnter the string: ");

scanf("%s",s);

for(i=0;i<f;i++)

F=-1;

do

{

// system("clear");

printf("\n\n\t*********** MENU ***********");

printf("\n\n\t1:FIFO\n\n\t2:LRU\n\n\t3:OPT\n\n\t4:EXIT");

printf("\n\n\tEnter your choice: ");

scanf("%d",&ch);

//system("clear");

switch(ch)

{

case 1:

for(i=0;i<f;i++)

{

F=-1;

}



FIFO(s,F,l,f);

break;

case 2:

for(i=0;i<f;i++)

{

F=-1;

}

lru(s,F,l,f);

break;

case 3:

for(i=0;i<f;i++)

{

F=-1;

}



opt(s,F,l,f);

break;

case 4:

exit(0);

}

printf("\n\n\tDo u want to continue IF YES PRESS 1\n\n\tIF NO PRESS 0 : ");

scanf("%d",&YN);

}while(YN==1);return(0);

}



//FIFO

void FIFO(char s[],char F[],int l,int f)

{

int i,j=0,k,flag=0,cnt=0;

printf("\n\tPAGE\t FRAMES\t FAULTS");

for(i=0;i<l;i++)

{

for(k=0;k<f;k++)

{

if(F[k]==s)

flag=1;

}



if(flag==0)

{

printf("\n\t%c\t",s);

F[j]=s;

j++;



for(k=0;k<f;k++)

{

printf(" %c",F[k]);

}

printf("\tPage-fault%d",cnt);

cnt++;

}



else

{

flag=0;

printf("\n\t%c\t",s);

for(k=0;k<f;k++)

{

printf(" %c",F[k]);

}



printf("\tNo page-fault");

}

if(j==f)

j=0;

}



}





//LRU

void lru(char s[],char F[],int l,int f)

{

int i,j=0,k,m,flag=0,cnt=0,top=0;

printf("\n\tPAGE\t FRAMES\t FAULTS");

for(i=0;i<l;i++)

{

for(k=0;k<f;k++)

{

if(F[k]==s)

{

flag=1;

break;

}

}



printf("\n\t%c\t",s);

if(j!=f && flag!=1)

{

F[top]=s;

j++;



if(j!=f)

top++;

}

else

{

if(flag!=1)

{

for(k=0;k<top;k++)

{

F[k]=F[k+1];

}



F[top]=s;

}

if(flag==1)

{

for(m=k;m<top;m++)

{

F[m]=F[m+1];

}
 
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