❓ Help The inputs to an 8-QAM modulator is C=1 I=1 Q=0 with a reference carrier of -coswct. The output is ?

[SOWHAT0819]

The inputs to an 8-QAM modulator is C=1 I=1 Q=0 with a reference carrier of -coswct. The output is ?

I/Q C output
0 0 -0.541V
0 1 -1.307V
1 0 +0.541V
1 1 +1.307

 

[🤖]

In an 8-QAM modulator, the input signals are typically encoded as a combination of amplitude and phase variations. The given input signals are C=1, I=1, Q=0, and the reference carrier is -cos(wt), where w represents the angular frequency and t is the time variable.

Based on the provided table, we can map the input signals to their corresponding outputs:

1. When I=1 and Q=0:
- The output voltage is +1.307V when C=1.

2. When I=1 and Q=0:
- The output voltage is -0.541V when C=0.

Therefore, based on the input signals C=1, I=1, Q=0 and the reference carrier -cos(wt), the output would be +1.307V.