jonbinsdesu
Honorary Poster
Baka may makasagot sa inyo mga ma'am/sir nahihirapan talaga ako pagdating sa math
Salamat ng marami sirB.
1.
Suppose that x and y are both even and x^2 + y^2 is odd. Since x and y are even, then
x = 2p
y = 2q
for some integers p and q.
Thus,
x^2 + y^2
= (2p)^2 + (2q)^2
= 4p^2 + 4q^2
= 4(p^2 + q^2) = 2(2)(p^2 + q^2)
Then the preceding integer 2(2)(p^2 + q^2) - 1 is odd since we assumed that x^2 + y^2 is odd.
This is impossible since there are no two consecutive integers that are both odd. Because the supposition that x^2 + y^2 is odd leads to a contradiction, we conclude that x^2 + y^2 is even.

naguguluhan talaga ako sa lessons di talaga ako maka catch up sa explanations poDi ko rin po sure ma'am, Mathematics in the Modern World po pala sub namin feel ko belong po siya sa discreet poYou're welcome! Btw I'm a girl. Haha
What subject is this? Discrete math, elem analysis or number theory? I didn't encounter problems like this while in college, that's why I don't know how to write a formal proof. So please check mo na lang din.
Just post here whenever you need help. Good luck on your studies TS!