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patulong boss salamat
 
Hello po pwede po ba pa open ? thanks po.

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Boss patulong hehe salamat!
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Detailed solution is given below.

Since the Reynold's Number of flow is 124527.200 > 4000 , flow is turbulent and Nikuradse equation can be used in this case.

Value of friction factor is f=0.017175.

The head loss/Energy loss in flow is 218.845 metres

Solution : m3 Given s=998-21 8.21 kg! M = 1.00 2 X10-3Ns/m2 L= 2000 m 50mm = 0.05m. v=2.5mis. g=9081ms?
Part (a) Stepi :- Find Reynolds Number Cre) Re=8VD у M =998-218 2.5x 0.05 11002 X10-3 124527-1956 > 4000 Hence flow flow is t
Step 2 Find f? 1 Vf 00869 ln (reff)-0.8 Put Re=124527, 1956. ² 124527-200 +4 난 = 0.869 In (124527.20 JF)-0-8 f= 0.017179 ( s
* Bisection method Iterative formula is given by where f(a) f(b) <o x= atb > 2 Hence Let f=n. VR fen) - I -0.869 4n (12452
fla= 0.015) = 0.5944 f(b=0.020) = -0.6245 0.015 +0.020 Hence 0.017500 In = atb 2 Iteration f(0.0175)= -0.0782 Hence root, ent
Iteration 4 f (0.016870 ) = 0.076248 hence re (0.016870,0.0175) Ny = 0.0168 70 +0.0175 = 0.017175 2
Error measured- absolute absolute ll 0-017175-0.017179 0.017179: 5-0.023x10-2 Hence Error = 0.023% (<0.025%)
= 0.017175X2000 X 2050? Head loss/ Energy loss in pipe is given by :- hg=fLv² 2-а Substituting values and solving h f 2x 9.81
 
hi guys sorry for the late replies, I was inactive due to my internet connection and I finished some errands. I replied and gave answers to everyone. pls refer to the new updated link because I will be unwatching this thread and lock it (the old other thread).

New updated link: https://phcorner.org/threads/free-unlimited-Çℎḙḡḡ-unlocks-comment-link.964173/ (THIS THREAD)

one last thing, I am looking for other Çℎḙḡḡ users that are here in PHC, I would like to collaborate and build a coordinated Çℎḙḡḡ Unlock Service Thread , please directly message me in my inbox if you want to make a change.

(THERE WILL BE NO ADJUSTMENTS IN THIS THREAD, THE LOCK AND UNWATCH IS FOR THE OLD PREVIOUS Çℎḙḡḡ UNLOCK THREAD I MADE)

Thank you and God Bless:)
 
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patulong po ts
 
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