🎓 Academic STATICS OF RIGID BODIES (PAHELP)

[PHC-kT]

Question sa malalakas na engineers dyan:

Paano idetermine yong angle ng x,y,z kung sine or cosine sa 3d force system

 

[6 T 9]

We can solve this problem by following these steps:
* Define position vectors for points A and B relative to point O.
* Subtract the position vectors to find the vector directed from A to B.
* Determine the magnitude of the resulting vector to find the distance between A and B.
Here's a breakdown of the solution process:
* Position vectors:
* Let's denote the position vector of point O as (0, 0).
* Given that the plane is at a distance of 5 km at an angle of 60° from O, its position vector can be represented as (5 * cos(60°), 5 * sin(60°)) = (2.5, 4.33).
* Similarly, the position vector of the train at a distance of 2 km and an angle of 25° from O is (2 * cos(25°), 2 * sin(25°)) = (1.8, 0.87).
* Vector directed from A to B:
* To find the vector directed from A to B, we subtract the position vector of O from the position vector of B and subtract the position vector of A from the position vector of B.
* Resulting vector (B w.r.t. O) - (A w.r.t. O) = (1.8, 0.87) - (2.5, 4.33) = (-0.7, -3.46).
* Magnitude of the resulting vector:
* The distance between A and B is the magnitude of the vector directed from A to B.
* Magnitude = sqrt((-0.7)^2 + (-3.46)^2) = sqrt(12.33) ≈ 3.5 km.
Therefore, the distance between the plane and the train at this instant is approximately 3.5 km.

ᑕᕼᗩTGᑭT hahahaha

trying to help lang, sorry kung mali

 

[PHC-kT]

We can solve this problem by following these steps:
* Define position vectors for points A and B relative to point O.
* Subtract the position vectors to find the vector directed from A to B.
* Determine the magnitude of the resulting vector to find the distance between A and B.
Here's a breakdown of the solution process:
* Position vectors:
* Let's denote the position vector of point O as (0, 0).
* Given that the plane is at a distance of 5 km at an angle of 60° from O, its position vector can be represented as (5 * cos(60°), 5 * sin(60°)) = (2.5, 4.33).
* Similarly, the position vector of the train at a distance of 2 km and an angle of 25° from O is (2 * cos(25°), 2 * sin(25°)) = (1.8, 0.87).
* Vector directed from A to B:
* To find the vector directed from A to B, we subtract the position vector of O from the position vector of B and subtract the position vector of A from the position vector of B.
* Resulting vector (B w.r.t. O) - (A w.r.t. O) = (1.8, 0.87) - (2.5, 4.33) = (-0.7, -3.46).
* Magnitude of the resulting vector:
* The distance between A and B is the magnitude of the vector directed from A to B.
* Magnitude = sqrt((-0.7)^2 + (-3.46)^2) = sqrt(12.33) ≈ 3.5 km.
Therefore, the distance between the plane and the train at this instant is approximately 3.5 km.

ᑕᕼᗩTGᑭT hahahaha

trying to help lang, sorry kung mali

yong concept lng ng sine at cos paps yong tanong ko HAHAHAHA

 

[6 T 9]

yong concept lng ng sine at cos paps yong tanong ko HAHAHAHA

sorry wala ako alam dyan

 

[PHC-Doraemon]

una pili ka muna kung ano gusto mo unahin kung saang POV
for example dyan sa problem, POV from Y-axis, ang makikita mo na lang is yung X and Z saka yung A (silip silip lang)
SOHCAHTOA lang
SINE=OPPOSITE/HYPOTENUSE
COSINE=ADJACENT/HYPOTENUSE
yung A is may 5km na hypotenuse, yung angle is 60,
opposite nya is yung Az, apply lang natin sohcatoa
may opposite kana saka hypotenuse kaya sine gagamitin
sin(60)=Az/5
Az=5sin(60)-----mas madali gantong format rekta mo na agad na ganto
yung isa naman yung Ax which is adjacent from angle
cosine naman dito,
cos(60)=Ax/5
Ax=5cos60

next lipat ka na ng POV kasi wala ka na makukuha
from X-axis naman (silip ka uli), ang makikita mo naman is Y at Z saka yung B na may 25 degrees
hypotenuse = 2km
opposite = Bz
adjacent = By
Bz=2sin(25)
By=2cos(25)

next from Z-axis
Kita mo rito yung X at Y
saka yung dalawang angle na medyo dark yung pagkablue
Dapat may values ka na ng Az,Ax,Bz, and By (nasolve na to sa taas)
unahin natin yung sa A,
yung hypotenuse naman yung nawawala
angle = 35 degrees
adjacent = Ax
opposite = Ay
unahin natin dito yung cosine kasi wala pa tayong value ng Ay
cos(35)=Ax/hyp
hyp=Ax/cos(35)
masosolve mo na value ng hypotenuse para magamit mo sa Ay
Ay=hyp*sin(35)
ganyan lang then proceed sa next