🔒 Closed Bartleby

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[Miraine]

unlocking

solution po

Step 1​

Given :

Volume of buffer solution = 100 ml

Concentration of starch solution = 2.92 μmol/mL = 2.92 x 10-6 mol/ml

Molar mass of starch = 342.30 g/mol

Step 2​

Moles of starch = Concentration (mol/ml) x Volume (ml)

=> Moles of starch = 2.92 x 10-6 x 100

=> Moles of starch = 2.92 x 10-4 moles

Mass of starch = Moles x molar mass

=> Mass of starch = 2.92 x 10-4 x 342.30

=> Mass of starch = 0.1 gm