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Answer & Explanation

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Ans. Area = 6.082 x 10-3 m2

Power = 6808.27 KW
Step-by-step explanation

Image transcription text
Ans. Given data: - CI m= juooo kilts ; ph= 150 man of water P = sgh P = 100 0 * 9. 81 x ( 15/ /1000 ) = 1471. 5 Pa Now first of all density of air for consideration 8 =m 10 00 0 = 0-1kg / m3 8 = 0.1 kg/ 2 3 Velocity ( V ) = Cb | 2 * 9. 81 XAP X Y Here v= P= density of ais cinder consideration. AP = Differential pressur by bitof tube = 1471. 5 Pa Cp = pitot tute Corst. = 0.85 V = 0.85N 2x 9 . 81 x 1471.5 X . 1 - 1 V = 456. 7 m /sec - ( Area ) Now we know Q = AXV A = & / v 1010000 3650 = 6. 082 x10 3 / 2 45 6.7 Area, A = 6.082 x15 3 /2 Ars .
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Image transcription text
we have Given mechanical efficiency nm = 0.6 2 nm = vol. (m/sec) x (AP in mm water column) x 10 102 x Power input to for ( KW) 0.6 = 10 0 0.0 X 150 ) 3600 X100 (02 X P P - 6808 . 27 KW Arg.