🔒 Closed Need Codes po ng java netbean for displaying employee name and there department

[rome22]

Mga lods I am just helping a friend since na hindi ako familiar sa javascript more on c++ coding ako lods please see picture for details

 

[PHC_Genaro]

Sino kaibigan mo?

 

[PHC_Genaro]

Familiar kasi yan, labexer na naka attach.

 

[rome22]

Familiar kasi yan, labexer na naka attach.

may sample codes ka ba dyan papi ?

 

[rome22]

Sino kaibigan mo?

Sir please help meron ba kayo dyan copy ng codes ?

 

[Carly_Rose]

java lang po alam ko. e sosorting po ba with name and there department?

 

[Arcturus]

eto ts pa try nalang

public class Rome22
{
   public static void main(String[] args) {
       String employee [][] = {            
                //employee
                {"Zuch ", "Huhg ", "Adam ", "Nathan ", "Erick "},
                //department
                {"SITE ", "CN ", "COE ", "CBAA ", "CEDE "},
            };
       int column = 5;
       int row = 1;
       //Save the 2D array into 1D array but only the names
       String[] employee1D = new String[column];
       int it = 0;
       for(int i = 0; i < row ; i++) {
           for(int j = 0 ; j < column ; j++) {
               employee1D[it] = employee[i][j];
               it++;
           }
       }
       //Sort the 1D array
       for(int i = 0 ; i < employee1D.length - 1; i++) {
           for(int j = i + 1 ; j < employee1D.length ; j++) {
               if(employee1D[i].compareTo(employee1D[j]) > 0) {
                   String temp = employee1D[i];
                   employee1D[i] = employee1D[j];
                   employee1D[j] = temp;
               }
           }
       }
       //Print the 2D sorted Array
       System.out.println("Name\t\t\tDepartment");
       int x = 0; // use to iterate the 1D array
       for(int i = 0 ; i <= 2 ; i++) {
           for(int j = 0 ; j < column; j++) {
               //Check if the Sorted 1D array is equal to the names in 2D array to get the corresponding Department
               if(employee[0][j].equals(employee1D[x])) {
               System.out.println(employee1D[x] +"\t\t\t"+ employee[1][j]);
               if(x < 4)
                   x++;
          }
       }
    }
  }
}

 

[rome22]

eto ts pa try nalang

public class Rome22
{
   public static void main(String[] args) {
       String employee [][] = {           
                //employee
                {"Zuch ", "Huhg ", "Adam ", "Nathan ", "Erick "},
                //department
                {"SITE ", "CN ", "COE ", "CBAA ", "CEDE "},
            };
       int column = 5;
       int row = 1;
       //Save the 2D array into 1D array but only the names
       String[] employee1D = new String[column];
       int it = 0;
       for(int i = 0; i < row ; i++) {
           for(int j = 0 ; j < column ; j++) {
               employee1D[it] = employee[i][j];
               it++;
           }
       }
       //Sort the 1D array
       for(int i = 0 ; i < employee1D.length - 1; i++) {
           for(int j = i + 1 ; j < employee1D.length ; j++) {
               if(employee1D[i].compareTo(employee1D[j]) > 0) {
                   String temp = employee1D[i];
                   employee1D[i] = employee1D[j];
                   employee1D[j] = temp;
               }
           }
       }
       //Print the 2D sorted Array
       System.out.println("Name\t\t\tDepartment");
       int x = 0; // use to iterate the 1D array
       for(int i = 0 ; i <= 2 ; i++) {
           for(int j = 0 ; j < column; j++) {
               //Check if the Sorted 1D array is equal to the names in 2D array to get the corresponding Department
               if(employee[0][j].equals(employee1D[x])) {
               System.out.println(employee1D[x] +"\t\t\t"+ employee[1][j]);
               if(x < 4)
                   x++;
          }
       }
    }
  }
}

Thanks lods your da best

 

[Arcturus]

Thanks lods your da best

Pero di pwedeng ipasa nalang, dapat pag aralan mo din yan

 

[rome22]

java lang po alam ko. e sosorting po ba with name and there department?

Yes mam sorry delay response salamat sa pag pansin

 

[rome22]

Pero di pwedeng ipasa nalang, dapat pag aralan mo din yan

Sige lods sensya wala pa kong fundamentals sa java eh tinulungan ko lang kaibigan start palang ako with visual basic at C++ pero lods dadating din ako dyan