🔒 Closed C masters patulong: Linked Lists: FREE LOAD

[pineng]

Patulong po mga master sa C programming:

Given a linked list:
Here I am

H-e-r-e-(space)-I-(space)-a-m-

: Count the number of words in a linked list.
Dapat ang sagot po jan ay 3.
Hmmm, may idea po ba kayo jan kung paano maiimplement?

TIA

Loadan ko po ng 50 makakasagot hehe.

 

[pineng]

up

 

[laxus456]

here i am lang ba talaga? or flexible na khit anong word?

 

[laxus456]

 

[laxus456]

pm mo ko para manotif xD gagawa rin kasi ako ng proj hahahahh

 

[laxus456]

nakagawa ako 2 different files, isang simple lang, nung sa screenshot tapos yung isa nadebug pag maraming space kunyari i __ am ___here (yung underscore ay space, for representation lang), magiging 3 pa rin bilang kahit gano karaming spaces basta may words

 

[laxus456]

linked list pala HAHAHA so sorry

 

[pineng]

cge waits

 

[homer_simpson]

Easy:

#include <stdio.h>
#include <stdlib.h>

int main(void) {
    size_t n = 2;
    char* mybuffer = malloc(sizeof(char) + n);
    printf("Enter string: ");
    size_t size = getline(&mybuffer, &n, stdin);
    int count = 0;
     for (int i=0; i<size; i++) {
         if ((mybuffer[i] == ' ' && mybuffer[i+1] != ' ') || mybuffer[i] == '\n') {
             ++count;
         }
     }
     free(mybuffer);
     printf("Num of words: %d\n", count);
     return 0;
}

 

[laxus456]

Easy:

#include <stdio.h>
#include <stdlib.h>

int main(void) {
    size_t n = 2;
    char* mybuffer = malloc(sizeof(char) + n);
    printf("Enter string: ");
    size_t size = getline(&mybuffer, &n, stdin);
    int count = 0;
     for (int i=0; i<size; i++) {
         if ((mybuffer[i] == ' ' && mybuffer[i+1] != ' ') || mybuffer[i] == '\n') {
             ++count;
         }
     }
     free(mybuffer);
     printf("Num of words: %d\n", count);
     return 0;
}

linked list ba to

 

[homer_simpson]

linked list ba to

Hindi. What's the point of linked list in this scenario? Ikaw, ano solution mo?

 

[laxus456]

Hindi. What's the point of linked list in this scenario? Ikaw, ano solution mo?

kung word search lang kasi nasend ko na dapat sa kanya, kaso linked list eh

 

[laxus456]

kung word search lang kasi nasend ko na dapat sa kanya, kaso linked list eh

word search through linked list

 

[laxus456]

Hindi. What's the point of linked list in this scenario? Ikaw, ano solution mo?

nasolutionan ko na rin pag maraming space, kunyari here __ i ____ am(considering na space yung underscore) 3 words pa rin yan

 

[laxus456]

di na ko gumawa para sa linked list lang

 

[laxus456]

so wala akong solution hahahaha

 

[pineng]

nagawa ko na po hehe. Linked lists need sa program eh. for easy deletion and insertion.