🔒 Closed Logical operators

[Aircon]

pahelp naman po

!x && x >= 3
value ng x = 7 true or false?

paki explain naman po and how siya icode using java

 

[PHC_Jayvee]

7 >= 3

mas malaki ba (or equal) si 7 kesa sa 3, oo syempre mas malaki si 7

 

[VoidHunter]

int x = 7;
boolean result = !x && x >= 3;
System.out.println(result);

The E×ρréššion "!x" evaluates to false because the logical NOT operator inverts the truth value of the E×ρréššion "x" (which is true since x = 7 is a non-zero integer). The E×ρréššion "x >= 3" evaluates to true since 7 is greater than or equal to 3. Therefore, the overall E×ρréššion "!x && x >= 3" evaluates to false && true, which results in a final value of false.

So the output of the above code would be "false", indicating that the E×ρréššion "!x && x >= 3" is false when x = 7.

 

[Aircon]

int x = 7;
boolean result = !x && x >= 3;
System.out.println(result);

The E×ρréššion "!x" evaluates to false because the logical NOT operator inverts the truth value of the E×ρréššion "x" (which is true since x = 7 is a non-zero integer). The E×ρréššion "x >= 3" evaluates to true since 7 is greater than or equal to 3. Therefore, the overall E×ρréššion "!x && x >= 3" evaluates to false && true, which results in a final value of false.

So the output of the above code would be "false", indicating that the E×ρréššion "!x && x >= 3" is false when x = 7.

nasa basic palang kasi kami paps pano siya icocode kapag ganitong lang


diko kasi siya macode ng tama pero alam kona yung sagot diko lang mapalabas

nasa basic palang kasi kami paps pano siya icocode kapag ganitong lang

int x = 7;
[/QUOTE]
[QUOTE="CR1T CARUZ, post: 25394135, member: 1470322"]
boolean result = !x && x >= 3;
System.out.println(result);

The E×ρréššion "!x" evaluates to false because the logical NOT operator inverts the truth value of the E×ρréššion "x" (which is true since x = 7 is a non-zero integer). The E×ρréššion "x >= 3" evaluates to true since 7 is greater than or equal to 3. Therefore, the overall E×ρréššion "!x && x >= 3" evaluates to false && true, which results in a final value of false.

So the output of the above code would be "false", indicating that the E×ρréššion "!x && x >= 3" is false when x = 7.

nageerror kasi sa compiler na gamit ko

 

[VoidHunter]

nasa basic palang kasi kami paps pano siya icocode kapag ganitong lang
View attachment 2534308

diko kasi siya macode ng tama pero alam kona yung sagot diko lang mapalabas


nageerror kasi sa compiler na gamit ko

Kung (x != 0) yan. True ang magiging output

 

[Aircon]

Kung (x != 0) yan. True ang magiging output
View attachment 2534330

pano siya icocode paps without boolean

 

[VoidHunter]

pano siya icocode paps without boolean

Ilipat mo lang yung condition sa baba