🔒 Closed PYTHON

[KilleerR8]

Pa-help naman po mga ka-phcorner. Hindi ko magawa ung magcacalculate ng total number ng holidays. Eto palang ung code na nagagawa ko pa-help po

import holidays
import calendar
from datetime import date

stmonth = int(input("Please enter starting month: "))
stday = int(input("Please enter starting month day: "))
styear = int(input("Please enter starting year: "))

print("1-Yes")
print("2-No")
lyear = int(input("Is the starting year a leap year?: "))
   
submonth = str(input("Please enter ending month: "))
subday = int(input("Please enter ending day: "))
endyear = date = int(input("Please enter ending year: "))

 

[cr4zyfr0g]

Anong year kana TS?

 

[KilleerR8]

Anong year kana TS?

Shs palang paps

 

[cr4zyfr0g]

Shs palang paps

Sana all nakapag python na samantalang samin dati HTML, CSS, JS, at may kunting C# lang. Mas advance pala sa school nyo TS

 

[KilleerR8]

Sana all nakapag python na samantalang samin dati HTML, CSS, JS, at may kunting C# lang. Mas advance pala sa school nyo TS

Naku advance nga pero ung teacher naman namin walang pakialam bigay lang nang bigay ng activity saamin hindi manlang nagtuturo hahaha

 

[cr4zyfr0g]

Naku advance nga pero ung teacher naman namin walang pakialam bigay lang nang bigay ng activity saamin hindi manlang nagtuturo hahaha

may python course ako dito sa gdrive naka save baka gusto mo send mo lang email mo sakin add kita

 

[KilleerR8]

may python course ako dito sa gdrive naka save baka gusto mo send mo lang email mo sakin add kita

Sige paps. Salamat

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[cr4zyfr0g]

Sige paps. Salamat
[Hidden content]

oks naba?

 

[KilleerR8]

oks naba?

Oks na paps

 

[zackmark29]

Suggest lang, once masolve mo na first solution mo, you should check programmatically the year if a leap year.

# https://docs.microsoft.com/en-us/office/troubleshoot/excel/determine-a-leap-year
def is_leap_year(year: int) -> bool:
    year = int(year)

    if not year % 4 == 0:
        print(f'{year} is not a Leap Year')
        return False

    print(f'{year} is a Leap Year')

    print('divisible by 4')

    if year % 100 == 0:
        print('and divisible by 100')
    else:
        print('and not divisible by 100')

    if year % 400 == 0:
        print('But also divisible by 400')

    return True


for year in (1990, 2000, 2021, 2024):
    is_leaf_year(year)
    print()

 

[Kr4mG3L0]

may python course ako dito sa gdrive naka save baka gusto mo send mo lang email mo sakin add kita

paps baka pwede maka hingi gusto ko din matuto sa python