🔒 Closed Sino po may alam nito

[If Else]

Create a C program that will determine the even numbers below is the sample output.

Enter a number: 4
4 is even number

 

[Arcturus]

Conditional operator lang po ito ts, magbasa kalang kahit konti lang magegets mo yan.
input % 2 == 0
printf("Even");
else
printf("Odd");

 

[cloverly]

another solution is

if (input&1)
printf("Odd");
else
printf("Even");

 

[If Else]

Conditional operator lang po ito ts, magbasa kalang kahit konti lang magegets mo yan.
input % 2 == 0
printf("Even");
else
printf("Odd");

#include <stdio.h>
int main() {
int num;
printf("Enter an number: ");
scanf("%d", &num);

(num % 2 == 0) ? printf("%d is even.", num) : printf("%d is odd.", num);
return 0;
}

 

[If Else]

Ta

#include <stdio.h>
int main() {
int num;
printf("Enter an number: ");
scanf("%d", &num);

(num % 2 == 0) ? printf("%d is even.", num) : printf("%d is odd.", num);
return 0;
}

Tama ba ito ts

 

[Arcturus]

Ta

Tama ba ito ts

if(num % 2 == 0)
printf("Even");
else
printf ("Odd");