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Answers and Explanations
Adiabatic compression:
P2 = 100580/(0.15^1.32)= 1230470.3957 Pa
P1 = 100580 Pa T1= 310.85 K T2 = 310.85/(0.15^0.32) = 570.4291 K
V2/V1 = 0.15
W12 = Cv(T1-T2)Assuming an average specific heat capacity of air of 0.834 Kj/Kg K at 900 Kelvin averrage combustion temperature
W12 = 0.834(310.85-570.4291)= -216.48897 Kj/Kg
Constant volume combustion
Combustion energy release = q23 = Cv(T3-T2) = 110/0.227 = 0.834(T3-570.4291) T3 = 1151.4620 K
(T3/T2) = 2483814.2072 Pa
Adiabatic expansion:
(V3/V4)^(k-1) = 1151.4620(0.15)^0.23 = 744.3044K
(0.15 x (T4/T3)) = 240830.4195 Pa
W34 = Cv(T3-T4) = 0.834( 1151.4620 - 744.3044)
= 339.5694 Kj/Kg