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[PHC-Ssamu]

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Paunlock paps parang awa mo na. hahaha Nawa'y magkatuluyan kayo ng crush mo paps. Salamat. hahaha

I open mo sakin.. Assistant ako ni covs.. Paps C 0 V 1 D baguhin mo yung instructions hoy HAHAHA

 

[PHC-Ssamu]

Ay dyan na pala amp HAHAHA

 

[C O V S]

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Paunlock paps parang awa mo na. hahaha Nawa'y magkatuluyan kayo ng crush mo paps. Salamat. hahaha

 

[C O V S]

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Paunlock paps parang awa mo na. hahaha Nawa'y magkatuluyan kayo ng crush mo paps. Salamat. hahaha

 

[-A-]

hindi akin to paps. hahaha
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ito nalang kulang.

 

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Salamat ng marami C 0 V 1 D

 

[PHC-Ssamu]

hindi akin to paps. hahaha
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ito nalang kulang.

 

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Salamat PHC-Ssamu

 

[PHC-Ssamu]

[XX='Craniax, c: 710711, m: 1202623'][/XX] Welcome paps

 

[PHC-Sakura]

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Lab you

 

[PHC-Sakura]

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ito paps
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[Metsuki]

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[C O V S]

[Hidden content]ito paps
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[C O V S]

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ganto po ang nakasulat
Question

An ideal Otto cycle engine with 15% clearance operates on .227kg/s of air; intake state is 100.58 kPa, 37.7C. The energy releasedduring combustion is 110 kJ/s. For hot-air standard with k = 1.32,compute: i. p, V, and T at each corner, ii. W, iii. e andpm

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dear student find detailed solution from this link...................................http://s3.amazonaws.com/answer-board-image/614b805c-0aab-4236-8fe7-4ee5db08c1f0.jpeg

 

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Other answer
Answers and Explanations
Adiabatic compression:
P2 = 100580/(0.15^1.32)= 1230470.3957 Pa
P1 = 100580 Pa T1= 310.85 K T2 = 310.85/(0.15^0.32) = 570.4291 K
V2/V1 = 0.15
W12 = Cv(T1-T2)Assuming an average specific heat capacity of air of 0.834 Kj/Kg K at 900 Kelvin averrage combustion temperature
W12 = 0.834(310.85-570.4291)= -216.48897 Kj/Kg
Constant volume combustion
Combustion energy release = q23 = Cv(T3-T2) = 110/0.227 = 0.834(T3-570.4291) T3 = 1151.4620 K
(T3/T2) = 2483814.2072 Pa
Adiabatic expansion:
(V3/V4)^(k-1) = 1151.4620(0.15)^0.23 = 744.3044K
(0.15 x (T4/T3)) = 240830.4195 Pa
W34 = Cv(T3-T4) = 0.834( 1151.4620 - 744.3044)
= 339.5694 Kj/Kg

 

[Beng beng908]

Eto po lods

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[ceejaybassist]

ty po..

 

[PHC-Ssamu]

[Hidden content]ito paps
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Sorry late.. Sakura chan HAHA

 

[PHC-Ssamu]

Eto po lods

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Answered by Expert Tutors

1. The story is entitled that way because shimenawa are used to symbolize ritual purification and to ward off evil spirits. However, Kazuya used a piece of this to end his life.
2. Onigiri is a rice ball.
3. The main characters in the story are, Kazuya, Yuko, Grandma, Jiro, and the author herself (I guess)
4. Naoko Kumagai
5. "Uncle Kazuya, my father's older brother, hung himself in the barn behind his house in Ishikari, just outside Sapporo in Hokkaido.", "As the eldest son, Kazuya was expected to stay in the house in Ishikari where he'd been born. He and Aunt Yuko brought up their two boys on the farm. I had met my uncle only once during a visit to Ishikari when I was ten, a hazy recollection, aside from his booming voice."
6. Distant relationship
7. Corruption was common in Japanese politics in Hokkaido; it was so common that people didn't particularly seem to be outraged by it.
8. "Kazuya went out the back door, carrying Jiro firmly under his arm. With the other hand, he picked up a circle of rope hanging on the fence by the shed. In the yard was a large oak tree with heavy, twisted branches. He wrapped the rope around my brother once, then pushed him to the trunk of the oak, winding the rope around and around."
9. Kazuya said, "He needs to learn to be a man."
10. Jiro jokes that the incident is possibly the reason he always, intuitively eats everything on his plate.