🎓 Academic Deleted

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Eto ang sagot ng isang expert sa CourseHero paps. Wala akong alam diyan sadyang may 2 tutor questions ako kaya ginamit ko lang, pang-experiment nalang din kung worth it bang magtanong sa kanila haha :ROFLMAO: Salamat pala sa question mo...

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Bale ang pagkakaintindi ko sa tanong ng nasa pic na binigay mo paps is to prove the associative laws lang naman at iprove na ang A ∪ (B∪C) = (A∪B) ∪ C. Di ako magaling sa math kaya out of my league ko ito paps haha. Sensya...
 
Pano ba magka free account sa course hero? Para di nako mahirapan magtanong dami subjects ko eh hirap na hirap akonsa mga pinapagawa haha
 
Dapat magbayad ka for subscription paps para makadownload or maka full view ka ng docs kasama na diyan ang unlimited 24/7 na ask expert tutors. Kung ayaw mong magbayad, alternative diyan ay mag-upload ka ng docs para makakuha ka ng rewards either pang-unlock ng docs or ask expert tutors. Sa sign-up may 2 questions ka na at sa pagverify ng email add mo ay 2 questions din. 10 docs/5 unlock kasama na ang ask questions. Mahirap talaga basta free lalong-lalo na na mismong tao ang sasagot ng tanong hindi lang isang engine.
 
BASE FROM TABLE VALUES
A={1,1,1,1,0,0,0,0}
B={1,1,0,0,1,1,0,0}
C={1,0,1,0,1,0,1,0}

PROVE: A n (B u C)=(A n B) u (A n C)

START FROM LEFT SIDE A n (B u C)

B u C = {1,1,0,0,1,1,0,0} u {1,0,1,0,1,0,1,0}
B u C = {1,0}
A n (B u C) = {1,1,1,1,0,0,0,0} n {1,0}

THEREFORE
A n (B u C) = {1,0} (1)LEFT SIDE

FROM RIGHT SIDE (A n B) u (A n C)
A n B = {1,1,1,1,0,0,0,0} n {1,1,0,0,1,1,0,0}
A n B = {1,0}

A n C = {1,1,1,1,0,0,0,0} n {1,0,1,0,1,0,1,0}
A n C = {1,0}

(A n B) u (A n C) = {1,0} u {1,0}

(A n B) u (A n C) = {1,0} (2)RIGHT SIDE

COMBINE 1 AND 2 SINCE BOTH ARE {1,0}

A n (B u C)=(A n B) u (A n C) (y)


ewan kung tama wahaha:LOL: good luck aral mabuti papsi

or try mo nalang per row yung substitution
A={1,}
B={1,}
C={1,}
hanggang sa pang 8th row

PROVE: A n (B u C)=(A n B) u (A n C)

START FROM LEFT SIDE A n (B u C)

B u C = {1} u {1}
B u C = {1} check in table is 1
A n (B u C) = {1} n {1}

THEREFORE
A n (B u C) = {1} (1)LEFT SIDE check in table is 1

FROM RIGHT SIDE (A n B) u (A n C)

A n B = {1} n {1}
A n B = {1} check in table is 1

A n C = {1} n {1}
A n C = {1} check in table is 1

(A n B) u (A n C) = {1} u {1}

(A n B) u (A n C) = {1} (2)RIGHT SIDE check in table is 1

COMBINE 1 AND 2 SINCE BOTH ARE {1}

A n (B u C)=(A n B) u (A n C) (y)
 
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