🔒 Closed Pa help po sa String problem nato

[derp123412]

Java program using String function/s that will convert vowels to asterisks. Your program should ask for a user input.


SAMPLE OUTPUT:

Enter a string: Happy New Year

New string: H*ppy N*w Y**r

 

[Arcturus]

hmm, pa try nito paps
using java.lang.StringBuilder

import java.util.Scanner;
public class test2 {
    static boolean isVowel(char c) {
        switch(c) {
        case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':
            return true;
        }
        return false;
    }
    static Scanner sc = new Scanner (System.in);
    public static void main(String []args){
        StringBuilder sb = new StringBuilder();
        System.out.println("Input: ");
        String input = sc.nextLine();
      
        for(int i = 0 ; i < input.length(); i++) {
            if(isVowel(input.charAt(i)))
                sb.append('*');
            else
            sb.append(input.charAt(i));
              
        }
        System.out.println("Output: "+sb.toString());
    }
}

or this kung hindi StringBuilder ang gagamitin

import java.util.Scanner;
public class test2 {
    static boolean isVowel(char c) {
        switch(c) {
        case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':
            return true;
        }
        return false;
    }
    static Scanner sc = new Scanner (System.in);
    public static void main(String []args){
        System.out.println("Input: ");
        String input = sc.nextLine();
        System.out.print("Output: ");
       
        for(int i = 0 ; i < input.length(); i++) {
            if(isVowel(input.charAt(i)))
                System.out.print("*");
            else
            System.out.print(""+input.charAt(i));
               
        }
    }
}

 

[phc-Darksin]

tutulong sana ako kso wala ako maintindihan

 

[derp123412]

hmm, pa try nito paps
using java.lang.StringBuilder

import java.util.Scanner;
public class test2 {
    static boolean isVowel(char c) {
        switch(c) {
        case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':
            return true;
        }
        return false;
    }
    static Scanner sc = new Scanner (System.in);
    public static void main(String []args){
        StringBuilder sb = new StringBuilder();
        System.out.println("Input: ");
        String input = sc.nextLine();
     
        for(int i = 0 ; i < input.length(); i++) {
            if(isVowel(input.charAt(i)))
                sb.append('*');
            else
            sb.append(input.charAt(i));
             
        }
        System.out.println("Output: "+sb.toString());
    }
}

or this kung hindi StringBuilder ang gagamitin

import java.util.Scanner;
public class test2 {
    static boolean isVowel(char c) {
        switch(c) {
        case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':
            return true;
        }
        return false;
    }
    static Scanner sc = new Scanner (System.in);
    public static void main(String []args){
        System.out.println("Input: ");
        String input = sc.nextLine();
        System.out.print("Output: ");
      
        for(int i = 0 ; i < input.length(); i++) {
            if(isVowel(input.charAt(i)))
                System.out.print("*");
            else
            System.out.print(""+input.charAt(i));
              
        }
    }
}

Maraming salamat po paps! tama po ang binigay mo na code.

 

[mrHazan]

Ito sa akin:

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner scan = new Scanner(System.in);
        
        String string = "";
        char[] stringArray;
        
        System.out.print("Input: ");
        string = scan.nextLine();
        stringArray = string.toCharArray();
        
        for (int i = 0; i < stringArray.length; i++)
        {
            switch(stringArray[i])
            {
                case 'a':
                case 'A':
                case 'e':
                case 'E':
                case 'i':
                case 'I':
                case 'o':
                case 'O':
                case 'u':
                case 'U':
                    stringArray[i] = '*';
                    break;
                default:
            }
        }
        
        string = new String(stringArray);
        System.out.print("\nOutput: " + string);
    }
}

 

[derp123412]

Ito sa akin:

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner scan = new Scanner(System.in);
       
        String string = "";
        char[] stringArray;
       
        System.out.print("Input: ");
        string = scan.nextLine();
        stringArray = string.toCharArray();
       
        for (int i = 0; i < stringArray.length; i++)
        {
            switch(stringArray[i])
            {
                case 'a':
                case 'A':
                case 'e':
                case 'E':
                case 'i':
                case 'I':
                case 'o':
                case 'O':
                case 'u':
                case 'U':
                    stringArray[i] = '*';
                    break;
                default:
            }
        }
       
        string = new String(stringArray);
        System.out.print("\nOutput: " + string);
    }
}

parang ito gusto ipa gawa sa ami gamit loop at switch. maraming salamat po paps!

 

[mrHazan]

parang ito gusto ipa gawa sa ami gamit loop at switch. maraming salamat po paps!

Sa totoo lang may shorter version pa yan. GAgamit ka ng replaceAll. no loop, no switch.

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner scan = new Scanner(System.in);
        String string = "";
     
        System.out.print("Input: ");
        string = scan.nextLine();
        System.out.print("\nOutput: " + string.replaceAll("AEIOUaeiou", "*"));
    }
}

 

[derp123412]

Sa totoo lang may shorter version pa yan. GAgamit ka ng replaceAll. no loop, no switch.

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner scan = new Scanner(System.in);
        String string = "";
    
        System.out.print("Input: ");
        string = scan.nextLine();
        System.out.print("\nOutput: " + string.replaceAll("AEIOUaeiou", "*"));
    }
}

aahhhhh . . . . . . . . . . .

 

[twojuantwo]

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        System.out.print("Input: ");
        String myString = scan.nextLine().replaceAll("[AEIOUaeiou]", "*");
        System.out.format("Output: %s: ", myString);
    }

 

[pixkit]

parang ito gusto ipa gawa sa ami gamit loop at switch. maraming salamat po paps!

I hope your professor is asking you this requirement to train his students on loops and switch and NOT because he thinks this is the acceptable way to solve this problem because it's not.

 

[aking143]

Puro copy paste lg namn gawa namn kau ng bago ahahah

 

[derp123412]

I hope your professor is asking you this requirement to train his students on loops and switch and NOT because he thinks this is the acceptable way to solve this problem because it's not.

she told us to find an answer and if we don't find an answer she will explain it to us. I was just asking becuase i'm still new at using strings but i know the basics for loops and switch. thanks for your concern though

 

[fireclouu]

pasali ako

Scanner scanner = new Scanner(System.in);
System.out.print("Enter String: ");
String str = scanner.nextLine();

        // Prepare new line
        System.out.println();

        // Prepare container (concatenation method)
        String outStr = "";

        for(int i = 0; i < str.length(); i++) {
            // uses implicit casting
            boolean isMatched = Pattern.matches("[AEIOUaeiou]", "" + str.charAt(i));

            if(isMatched) {
                outStr += "*";
            } else {
                outStr += str.charAt(i);
            }
        }

        System.out.println(outStr);

 

[aa1012]

pasali ako

Scanner scanner = new Scanner(System.in);
System.out.print("Enter String: ");
String str = scanner.nextLine();

        // Prepare new line
        System.out.println();

        // Prepare container (concatenation method)
        String outStr = "";

        for(int i = 0; i < str.length(); i++) {
            // uses implicit casting
            boolean isMatched = Pattern.matches("[AEIOUaeiou]", "" + str.charAt(i));

            if(isMatched) {
                outStr += "*";
            } else {
                outStr += str.charAt(i);
            }
        }

        System.out.println(outStr);

This is by far the best solution I've read.

 

[homer_simpson]

read -p "Enter string: "; echo $REPLY | tr 'aeiou' '*'

 

[aa1012]

Ganda ng thread na ito. parang stackoverflow vibe. paligsahan ng solution sa tanong. ganyan sana lagi.

 

[homer_simpson]

#include <iostream>

int main(void) {
    std::string input;
    std::cout << "Enter input: ";
    std::getline(std::cin, input);
    for (char& c : input) {
        switch (c) {
            case 'A':
            case 'E':
            case 'I':
            case 'O':
            case 'U':
            case 'a':
            case 'e':
            case 'i':
            case 'o':
            case 'u':
                c='*';
                break;
            default:
                break;
        }
        std::cout << c;
    }
    std::cout << std::endl;
    return 0;
}