🔒 Closed Help how to only get characters

[Penpenqt69]

import java.util.Scanner;

public class LoveCalcu {

    public static void main(String[] args) {
        
        String yourname="";
        String crush="";
        Scanner heya=new Scanner (System.in);
        System.out.println("Enter Your Name:");
        yourname=heya.next();
        System.out.println("Enter Your Crush Name:");
        crush=heya.next();
        String yie=yourname+crush;
        System.out.println(yie);
        char[] characters = yie.toCharArray();
        int length = characters.length;
    for (int i = 0; i < length; i++) {
            for (int j = i + 1; j < length; j++) {
                if (characters[i] == characters[j]) {
                    int temp = j;//set duplicate element index
 
                    //delete the duplicate element by shifting the elements to left
                    for (int k = temp; k < length - 1; k++) {
                        characters[k] = characters[k + 1];
                    }
                    j--;
                    length--;//reduce char array length
 
                }
            }
        }
    String yiee = new String(characters);
    yiee = yiee.substring(0, length);
    int a=yie.length();
    int b=yiee.length();
    int c=a-b;
    System.out.println(c+" letter r duplicated bish");
    //eto na start ng condition paayos nalang concatination
           if(c==2 || c==1){
        System.out.println("Enemy");
    } else if (c==3 ||c==4){
    System.out.println("Friends");
    } else if (c==5 ||c==6) {
        System.out.println("Yie Lovers");
    } else if (c==7 ||c==8) {
        System.out.println("Affection");
    } else if (c>=9){   
        System.out.println("Married");
    } else {
        System.out.println("Invalid");
    }   
    System.out.println("String after duplicates r removed : " + yiee);
}
}

OUT PUT:
Enter Your Name:
1
Enter Your Crush Name:
2
12
0 letter r duplicated bish
Invalid
String after duplicates r removed : 12

ANG GUSTO KO PO SANANG GAWIN IS ONLY CHARACTERS LANG ANG MAKUKUHA PERO PAG NAG INPUT NUMBERS NAGBIBILANG PADIN SYA.

THANK YOU!!!

 

[FreeAllYouCan-OFFICIAL]

try catch method sir

 

[Penpenqt69]

try catch method sir

Saan ko po sya ilalagay?

 

[khaizer002]

Gawan mo ng condition sa loob ng loop mo
if != number
char++

tama ba pagkakaintindi ko? haha

 

[pixkit]

Pleasr don't put everything under the main() section. It doesn't make the code readable and leads to unwanted bugs.

The way you wrote your code is like this:

WhatISYourName?howOldAreyou?ifuouareanIture?

Do you see how difficult it is to read such sentence? It's no different when writing code. I am not even talking about whether your logic is correct. It's a question of legibility and readability.

 

[fazz12]

Java po yan boss, not JavaScript.
Next, aralin mo yung regex, or regular E×ρréššions. yan yung gagamitin mong pangfilter ng mga input.

sample code below. ikaw na bahala mag integrate sa program mo. bawal kasi spoonfeed dito:

import java.util.Scanner;
import java.util.regex.*;

public class JavaRegex {

public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner myScanner = new Scanner(System.in); //object that gets input

//get the input here
System.out.println("Enter your name: ");
String yourname = myScanner.nextLine();

//the pattern.it means alpha and space only. ie. san miguel, santa claus
String pattern = "^[A-Za-zñÑ\\s]+$";

//compile the pattern
Pattern regexPattern = Pattern.compile(pattern);

//fetch the pattern to the matcher object
Matcher matcher = regexPattern.matcher(yourname);

//actual line of code that tests whether the pattern is followed
boolean isMatch = matcher.matches();


if(isMatch)
{
//input has only alpha and space characters
System.out.println("Input contains only Alpha chars");
}
else
{
//input has characters other than alpha and space
System.out.println("Input contains non Alpha chars");
}

}

}