🔒 Closed Help!! math problem

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the tens digit of a number is 3 less than the units digit. if the number is divided by the sum of the digits. the quotient is 4, the remainder is 3, what is the original number?
------------
Let the original number be 10t+u
----------
Equations:
t = u - 3
(10t+u)/(t+u) = 4 + 3/(t+u)
-------------------------------
Simplify the 2nd equation:
10t+u = 4(t+u) + 3
10t+u = 4t+4u + 3
6t - 3u = 3
2t -u = 1
------------------------


Form the system of two equations:
t = u -3
2t -u = 1
----------------
Substitute to solve for "u":
2(u-3)-u = 1
2u-6-u = 1
u = 7
-------------
Substitute into t = u-3 to solve for "t":
t = 7-3 = 4
====================
The number is 47
=======================
Cheers,
San H.

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the tens digit of a number is 3 less than the units digit. if the number is divided by the sum of the digits. the quotient is 4, the remainder is 3, what is the original number?
------------
Let the original number be 10t+u
----------
Equations:
t = u - 3
(10t+u)/(t+u) = 4 + 3/(t+u)
-------------------------------
Simplify the 2nd equation:
10t+u = 4(t+u) + 3
10t+u = 4t+4u + 3
6t - 3u = 3
2t -u = 1
------------------------


Form the system of two equations:
t = u -3
2t -u = 1
----------------
Substitute to solve for "u":
2(u-3)-u = 1
2u-6-u = 1
u = 7
-------------
Substitute into t = u-3 to solve for "t":
t = 7-3 = 4
====================
The number is 47
=======================
Cheers,
San H.

source: (You do not have permission to view the full content of this post. Log in or register now.)
Naysu pwede din pala dito mga math problems, brokenheart problem pwede din kaya?
 
the tens digit of a number is 3 less than the units digit. if the number is divided by the sum of the digits. the quotient is 4, the remainder is 3, what is the original number?
------------
Let the original number be 10t+u
----------
Equations:
t = u - 3
(10t+u)/(t+u) = 4 + 3/(t+u)
-------------------------------
Simplify the 2nd equation:
10t+u = 4(t+u) + 3
10t+u = 4t+4u + 3
6t - 3u = 3
2t -u = 1
------------------------


Form the system of two equations:
t = u -3
2t -u = 1
----------------
Substitute to solve for "u":
2(u-3)-u = 1
2u-6-u = 1
u = 7
-------------
Substitute into t = u-3 to solve for "t":
t = 7-3 = 4
====================
The number is 47
=======================
Cheers,
San H.

source: (You do not have permission to view the full content of this post. Log in or register now.)
Tyvm zer!!!
 
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