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[SOWHAT0819]

Question 6Consider a power amplifier that shows the highest output power when it is terminated by a load resistance of 5 ΩΩ. The power amplifier needs to be connected using a matching circuit to a 50 ΩΩ antenna. Design a two-element lumped matching circuit operating at 1 GHz to match from the low impedance of 5 ΩΩ to the antenna impedance. Use a shunt CC and series LL to match from load to source. Use an on-line Smith chart tool or QUCS to find the component values e.g. You do not have permission to view the full content of this post. Log in or register now.. What is the value of LL? (in nH) 23.87Incorrect0 / 1 point7.Question 7Develop a two-element lumped element matching network to match a complex load impedance ZL=RL=250−ȷ200ΩZL=RL=250−ȷ200Ω to a source impedance ZS=RS=50ΩZS=RS=50Ω at 1 GHz. Use a series LL and shunt CC to match from load to source. Use an on-line Smith chart tool or QUCS to find the component values e.g. You do not have permission to view the full content of this post. Log in or register now.. What is the value of CC? (in pF) 6.37Incorrect0 / 1 point8.Question 8Develop a two-element lumped element matching network to match a complex load impedance ZL=RL=250−ȷ200ΩZL=RL=250−ȷ200Ω to a source impedance ZS=RS=50ΩZS=RS=50Ω at 1 GHz. Use a series LL and shunt CC to match from load to source. Use an on-line Smith chart tool or QUCS to find the component values e.g. You do not have permission to view the full content of this post. Log in or register now.. What is the value of LL? (in nH) 31.83Incorrect0 / 1 point9.Question 9Design a lumped-element matching network to match a complex load impedance ZL=RL=200−ȷ100ΩZL=RL=200−ȷ100Ω to a 100Ω100Ω transmission line at 500 MHz. Use a series CC and shunt LL to match from load to source. Use an on-line Smith chart tool to find the component values e.g. You do not have permission to view the full content of this post. Log in or register now.. What is the value of CC? (in pF)3.18Incorrect0 / 1 point10.Question 10Design a lumped-element matching network to match a complex load impedance ZL=RL=200−ȷ100ΩZL=RL=200−ȷ100Ω to a 100Ω100Ω transmission line at 500 MHz. Use a series CC and shunt LL to match from load to source. Use an on-line Smith chart tool to find the component values e.g. You do not have permission to view the full content of this post. Log in or register now.. What is the value of LL? (in nH)31.83Incorrect0 / 1 point11.Question 11Design a lossless L-section matching circuit to match a load of ZL=150−j200ΩZL=150−j200Ω to a 100Ω100Ω generator at 3GHz.See the normalized picture above (normalized to 100Ω100Ω) and give the value for bb (also normalized to 100Ω100Ω). Use b>0b>0.0.7454Incorrect0 / 1 point12.Question 12Design a lossless L-section matching circuit to match a load of ZL=150−j200ΩZL=150−j200Ω to a 100Ω100Ω generator at 3 GHz. Use b>0b>0See the normalized picture above and give the value for xx (also normalized to 100Ω100Ω). Use again b>0b>0.2Incorrect

 

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For question 6, to design a two-element lumped matching circuit operating at 1 GHz to match from the low impedance of 5 Ω to the antenna impedance of 50 Ω, using a shunt capacitor (CC) and series inductor (LL), the value of LL was calculated as 23.87 nH.

For question 7, to match a complex load impedance ZL = 250 - j200 Ω to a source impedance ZS = 50 Ω at 1 GHz using a series inductor (LL) and shunt capacitor (CC), the value of CC was calculated as 6.37 pF.

For question 8, the value of LL to match the same load impedance ZL = 250 - j200 Ω to the source impedance ZS = 50 Ω using the same configuration of series LL and shunt CC was calculated as 31.83 nH.

For question 9, to match a complex load impedance ZL = 200 - j100 Ω to a 100 Ω transmission line at 500 MHz using a series capacitor (CC) and shunt inductor (LL), the value of CC was calculated as 3.18 pF.

For question 10, to match the same load impedance ZL = 200 - j100 Ω to a 100 Ω transmission line at 500 MHz using a series CC and shunt LL, the value of LL was calculated as 31.83 nH.

For question 11, designing a lossless L-section matching circuit to match a load of ZL = 150 - j200 Ω to a 100 Ω generator at 3 GHz, the value for b (normalized to 100 Ω) was calculated as 0.7454.

For question 12, in the same scenario as question 11, the value for x (normalized to 100 Ω) with b > 0 was calculated as 2.

Please let me know if you need further assistance or clarification on any of the questions!