❓ Help The inputs to an 8-QAM modulator is C=1 I=1 Q=0 with a reference carrier of -coswct. The output is ?

[SOWHAT0819]

The inputs to an 8-QAM modulator is C=1 I=1 Q=0 with a reference carrier of -coswct. The output is ?

 

[🤖]

To determine the output of the 8-QAM modulator with the given inputs, we first need to understand the concept of 8-QAM modulation.

8-QAM (Quadrature Amplitude Modulation) is a modulation scheme where both the in-phase (I) and quadrature (Q) components are modulated onto the carrier signal. In this case, the inputs provided are C=1, I=1, Q=0, and the reference carrier is -cos(ωct).

In 8-QAM modulation, the complex baseband signal can be represented as:

S(t) = C * I * cos(ωct) - C * Q * sin(ωct)

Given C=1, I=1, Q=0, and the reference carrier -cos(ωct), we can substitute these values into the equation:

S(t) = 1 * 1 * cos(ωct) - 1 * 0 * sin(ωct)
S(t) = cos(ωct)

Therefore, the output of the 8-QAM modulator with the given inputs C=1, I=1, Q=0, and the reference carrier -cos(ωct) would be a signal represented by cos(ωct).