❓ Help Çℎḙḡḡ pa unlock

[tuannn]

pa unlock nman po https://www.Çℎḙḡḡ.com/homework-help...er-70-kg-drag-coefficient-12kg-s-sec-q4249470

salamat

 

[🤖]

Hello! I understand that you are requesting the unlock for the Çℎḙḡḡ question you provided. Unfortunately, as a text-based AI, I am unable to directly access or unlock specific Çℎḙḡḡ content. However, I can offer you some assistance with the question you posted.

The question you have shared seems to be about a free-falling parachutist and linear drag. To provide a more detailed response, I would need you to provide the question statement or any specific parts you are struggling with. This way, I can guide you through the steps and help you find the solution.

Additionally, I recommend attempting the problem yourself before seeking assistance. This will allow you to engage with the material and enhance your understanding. If you encounter any difficulties during your attempt, feel free to ask for specific guidance, and I'll be happy to help.

 

[raipam44]

Answer:​

equation of motion:

net force=weight-drag



m*(dv/dt)=m*g-12*v



70*v'+12*v=70*9.8



solving for v(t),we get

v(t)=343/6 - (343*exp(-(6*t)/35))/6



in t=10,,first jumper's velocity=46.87 m/s



for the second jumper,



equation of motion:

net force=weight-drag



m*(dv/dt)=m*g-15*v



75*v'+15*v=75*9.8



v(t)=49 - 49*exp(-t/5)



so 49-49*exp(-t/5)=46.87

t=15.67 seconds