Solo 2 month Spotipay

[kr4t]

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unang tamang reply!

 

[Aebiii]

keep sharing papsi!

 

[NESTEA APPLE]

2x^2 - 5x + 2 = 0 are x = 2 and x = 1/2

 

[wuff]

(x−2)(2x−1)

 

[PHC-Kaito]

x=2,2½

 

[IcaruzXIV]

X = 2 & 0.5

 

[Lucifer-Morningstar]

2x^2 - 5x + 2 = 0 are x = 2 and x = 1/2.

 

[kr4t]

mali daw sabi ni ᑕᕼᗩTGᑭT haha

 

[Yuki_bae]

x=1/2,2

 

[Pekyuuu]

2x^2 - 4x - x + 2 = 0

2x(x - 2) -1(x - 2) = 0

(x - 2)(2x - 1) = 0

 

[wuff]

0

 

[kr4t]

si ᑕᕼᗩTGᑭT kasi nagbigay nyan

eto solution nya

Solution: To solve for x, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation: ax^2 + bx + c = 0.

In this case, a = 2, b = -5, and c = 2. Substituting these values into the quadratic formula, we get:

x = (-(-5) ± sqrt((-5)^2 - 4(2)(2))) / 2(2)

x = (5 ± sqrt(17)) / 4

di pa complete yan

 

[haji09]

X=1/2 or 2

 

[PHC-Kaito]

2x+1=0,x=−½
x+2=0,x=−2

 

[Pekyuuu]

x = 2 or x = 1/2

 

[wuff]

x = (5 ± sqrt(17)) / 4

 

[Yuki_bae]

x =(5+√9)/4=(5+3)/4= 2.000

or:

x =(5-√9)/4=(5-3)/4= 0.500

 

[Pekyuuu]

x = (5 + sqrt(17)) / 4

x = (5 - sqrt(17)) / 4

 

[kr4t]

number ang possible values ng x, may clue na sa taas complete the solution nalang sensya mahirap pala to simple problem lang hininingi ko kay ᑕᕼᗩTGᑭT pero eto binigay haha

 

[PHC-Kaito]

Using the quadratic formula:

The quadratic formula is:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 2, b = -5, and c = 2

Plugging in these values, we get:

x = (-(-5) ± sqrt((-5)^2 - 4(2)(2))) / (2(2))

Simplifying:

x = (5 ± sqrt(17)) / 4

Therefore, the solutions to the equation are x = (5 + sqrt(17))/4 or x = (5 - sqrt(17))/4.