🎓 Academic Calculus

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leter D lods

f(u) = √u (5-u⁶)
f(u) = u½ (5-u⁶)
f'(u) = u½ (0-6u⁵) + (5-u⁶) (1/2 u-½)
f'(u) = u½(-6u⁵) + (5-u⁶)(1/2u-½)
f'(u) = -6u^11/2 + (5-u⁶)/2√u
 
leter D lods

f(u) = √u (5-u⁶)
f(u) = u½ (5-u⁶)
f'(u) = u½ (0-6u⁵) + (5-u⁶) (1/2 u-½)
f'(u) = u½(-6u⁵) + (5-u⁶)(1/2u-½)
f'(u) = -6u^11/2 + (5-u⁶)/2√u
Maraming salamat poooo hehe tagal ko nang stuck sa item nato di ko na talaga kaya haha
 
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Leonz

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