🎓 Academic Sa magagaling mag MATH Jan.

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Pa sagot naman nito mga lods

The fifth number plus the first number equals sixteen.

The sum of twice the second number plus 1 equals the fifth number.

The fourth number is one more than the second number.

The first number is one less than twice the second number.

The second number plus the third number equals ten.

The sum of all five numbers is 31.
 
The fifth number plus the first number equals sixteen.

The sum of twice the second number plus 1 equals the fifth number.

The fourth number is one more than the second number.

The first number is one less than twice the second number.

The second number plus the third number equals ten.

The sum of all five numbers is 31.


let
a+b+c+d+e=31

e+a=16

e=2b+1

d=b+1

a=2b-1

b+c=10 or c=10-b

solve for b first

substitute in
a+b+c+d+e=31

(2b-1) + b + (10-b) + (b+1) + (2b+1) = 31

5b=31-11

b=4

sub b in a,c,d,e

a=7
c=6
d=5
e=9
 
The fifth number plus the first number equals sixteen.

The sum of twice the second number plus 1 equals the fifth number.

The fourth number is one more than the second number.

The first number is one less than twice the second number.

The second number plus the third number equals ten.

The sum of all five numbers is 31.


let
a+b+c+d+e=31

e+a=16

e=2b+1

d=b+1

a=2b-1

b+c=10 or c=10-b

solve for b first

substitute in
a+b+c+d+e=31

(2b-1) + b + (10-b) + (b+1) + (2b+1) = 31

5b=31-11

b=4

sub b in a,c,d,e

a=7
c=6
d=5
e=9
Thank you lods
 
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