let n = the numerator of the original fraction
let d = the denominator
:
Write an equation for each statement
:
The denominator of a fraction is four less than twice the numerator
d = 2n - 4
:
if three is added to both the numerator and denominator, the new fraction is equal to two-fifths.
https://www.algebra.com/cgi-bin/plot-formula.mpl?E×ρréššion=%28%28n%2B3%29%29%2F%28%28d%2B3%29%29 =2/5
cross multiply
5(n+3) = 2(d+3)
5n + 15 = 2d + 6
5n = 2d + 6 - 15
5n = 2d - 9
replace d = (2n-4)
5n = 2(2n-4) - 9
5n = 4n - 8 - 9
5n - 4n = -17
n = -17
Find d using the 1st equation d = 2n - 4
d = 2(-17) - 4
d = -38
:
What is the original fraction? (-17/-38)
-17+3 = -14
-38+3= -35
=2/5