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[Pedroy]

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SOLVING PROBLEM MUNA!

MATH PROBLEM(hindi ko to assignment mga idol)

Q1: find the center and radius of the circle.
1. x²+y²-20x-10y+89= 0

Q2: convert angles to radians
1. 320°42'78"

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thankyou sa support!

 

[Deleted member 1268849]

Try TS ah hahaha
Q1 Answer: The center of the circle is point C=(10,5)
The radius of the circle is r=6

 

[Doyen]

Support na lang ts
Keep sharing

 

[Pedroy]

Try TS ah hahaha
Q1 Answer: The center of the circle is point C=(10,5)
The radius of the circle is r=6

nasan solution mo paps

 

[Pedroy]

Support na lang ts
Keep sharing

salamat po

 

[Deleted member 1268849]

nasan solution mo paps

Solution : (x2−20x+100)+(y2−10y+25)(x2−20x+100)+(y2−10y+25)(x−10)2+(y−5)2=−89+100+25=36=36

Radius: 36=6

 

[Pedroy]

Solution : (x2−20x+100)+(y2−10y+25)(x2−20x+100)+(y2−10y+25)(x−10)2+(y−5)2=−89+100+25=36=36

Radius: 36=6

goodwork! feedback ka nalang kung working!

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[Deleted member 1268849]

goodwork! feedback ka nalang kung working!
[Hidden content]

Working master

 

[Pedroy]

Working master

salamat po

 

[Deleted member 1268849]

salamat po

Salamat din master

 

[Deleted member 1268849]

Sagutin ko na rin isa? Hahaha

 

[Pedroy]

Sagutin ko na rin isa? Hahaha

ipaubaya mo na sa nangangailangan master HAHAHAHA marami ka naman acc e

 

[Pedroy]

avail pa po yung Q2:
sayang naman po yung acc hehe

 

[Doyen]

Try lang sa Q2:

320°+((42'/60)+(78"/3600))

320°+(0.7+0.021)

320.72×(π/180)

5.598 rad

 

[Pedroy]

Try lang sa Q2:

320°+((42'/60)+(78"/3600))

320°+(0.7+0.021)

320.72×(π/180)

5.598 rad

parang mali yata lods

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[Doyen]

parang mali yata lods

[Hidden content]

Sorry lods try lang naman po

 

[Pedroy]

Sorry lods try lang naman po

ayos lang idol, noproblem

 

[KIRA KAKUSHI]

Support here master

 

[Pedroy]

Support here master

salamat po

 

[TS_Junkie]

320°42'78"= 320°+43+18
=320°+43'(1°/60')+18"(1° /3600")
=320°+. 71667°+. 005°
=320.7216667°x(π/180°)
=5.5976rad ≈ 6rad