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[Metsuki]

Kung wala po pa unlock po salamat
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[Starrdust]

SSSSHHHH12 baka online ka lods.

 

[SSSSHHHH12]

wait lods

 

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Question:​

[IMG alt="A pulley has a constant angular acceleration of 3 rad/s?. When the angular
velocity is 2rad/sec, that the total acceleration of a point on the rim of the pulley
is 10ft/s?. Compute the diameter of the pulley.
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---

Answer:​

Step 1
α=Angular acceleration=3 rad/s2ω=Angular velocity=2 rad/sa=Total acceleration=10 ft/s2r=Radius of pulleyα=Angular acceleration=3 rad/s2ω=Angular velocity=2 rad/sa=Total acceleration=10 ft/s2r=Radius of pulley
Step 2
Centripetal acceleration is given by
ac=ω2rac=ω2r
Tangential acceleration is given by
at=αrat=αr
Total acceleration is given by
a=a2c+a2t−−−−−−√⇒a=(ω2r)2+(αr)2−−−−−−−−−−−−√⇒a2=(ω2r)2+(αr)2⇒a2=ω4r2+α2r2⇒a2=r2(ω4+α2)⇒r=a2ω4+α2−−−−−√=aω4+α2√⇒r=1024+32√⇒r=2 fta=ac2+at2⇒a=(ω2r)2+(αr)2⇒a2=(ω2r)2+(αr)2⇒a2=ω4r2+α2r2⇒a2=r2(ω4+α2)⇒r=a2ω4+α2=aω4+α2⇒r=1024+32⇒r=2 ft
Diameter is given by
d=2r=2×2=4 ftd=2r=2×2=4 ft
The diameter of the pulley is 4 ft.
Step 3
Answer:
4 ft

 

[Metsuki]

Pwede po screenshot? Salamat narin

 

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[SSSSHHHH12]

pa mark nalang as sulution lods kung ok lang hehe salamat