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[JhaycelJhaycel]

Need a little help lang po dito sa aking assignment sa integral calculus. Hindi kasi ito naturo saamin kaya't talagang hindi ko alam ang isasagot ko hehe.
Or baka po pwede pa-unlock/pa-capture and ask sa Çℎḙḡḡ thankyou so much!

 

[faye422]

A.
1. X + C
2. 2/3 √x³ + C

B. Solution A= integral of (4-x²) , from 1 to 2
= 4x - x³/3 from 1 to 2
= [4(2) - 2³/3] - [4(1) - 1³/3]
A= (8 - 8/3) - (4 - 1/3)
= (16/3) - (11/3) = 5/3

 

[faye422]

Pasensya na lodi. Yan lng nakayanan. Di ko kaya true or false. Mahina ako jan.

 

[JhaycelJhaycel]

View attachment 1427229View attachment 1427230
Pasensya na lodi. Yan lng nakayanan. Di ko kaya true or false. Mahina ako jan.

Maraming salamat idol <3 lab u

 

[Deleted member 1371840]

A.
1. x + C
2. (2/3) * (tan (x))^(3/2) + C

B.
The graph is a parabola opening downward, with vertex at (0, 4). The area by integration is 5/3 sq. units.

C.
1. 10/3
2. (8/27)(4sqrt(10) - 5)

D.
Same with the procedure above, except the final answer should be x sin (x) + cos (x) - 1

E.
Same with the procedure above

 

[Deleted member 1371840]

I.
1. True
2. False
3. True
6. True
7. False
8. False
9. True
10. True

If you need help in providing for the examples, just post here.