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🔒 Closed Sino papaunlock? (Coursehero)
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1 person= 1 document hahaha
If gusto nyo marami bawal hahah dejk pwede reach out kayo
Heathcliff
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paunlock po salamat
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paunlock po salamat
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pa try paps
pa try paps
Heathcliff
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maraming salamat po
Cherprang Areekul
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Pa unlock po boss, Thanks
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tantan0398
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Paunlock ts.salamat
Paunlock ts.salamat
(A) 0.10562 m (negative correction)
(B) 0.0017 m (negative correction)
(C) 459.198 m
Step-by-step explanation
Given data:
Standard Length of tape, l = 30 m
Measured length on the slope, L = 459.20 m
Difference in elevation, h= 1.25 m
Standardization at temperature = 100 and pull = 50N
The measurement at temp = 150 and pull = 75N
The cross sectional area of tape, A = 6.50 mm2 = 6.5*10-6 m2
modulus of elasticity, E = 200 GPa = 2 *106 kN/m2
mass per unit length of tape, m = 0.075 kg/m
Let the coefficient of thermal expansion of the tape = 12*10-6/0C
(A) The Total correction per tape length:
Corrections have to be worked out for temperature, pull and sag of the tape;
Correction for temperature = lαT = 30 * (12*10-6) * (15 - 10) = 0.0018 m
Correction for pull = AEΔPl = [(75 - 50) * 30] / (6.5*10-6*200*109) = 0.00058 m
Weight of the tape = 0.075(kg/m)*9.81*30 = 22.0725N
Correction for sag = l(wl)2/24P2 = 30*(22.0725)2/(24*752) = 0.108 m
So, Total correction per tape length = 0.0018+0.00058-0.108 = -0.10562 m (correction is negative)
(B) The correction for slope:
Correction for slope = 2∗Lh2 = 1.252/(2*459.20) = 0.0017 m, this correction is always negative.
(C) The horizontal distance:
Using pythagoras theorem, Horizontal distance,D = L2−h2 = (459.20)2−(1.25)2 = 459.198 m
thelastswordsma
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paano yan lods ?
thelastswordsma
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sana lods
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sana lods
Cherprang Areekul
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Thanks
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