SOLVED: The heat required to remove from beef 110 kg is 36,437 kJ which will be cooled from 20°C to -18°C. The specific heat above freezing is 3.23 kJ/kg·°C and latent heat of fusion is 233 kJ/kg. If the specific heat below freezing is 1.68 kJ/kg·°C, (a) find the freezing temperature. (b)...
baka naman di po kayo busy
:ALERTA:Link for twitter :ALERTA:
need ko lang po ng follower kahit mga 20 lang. thanks
para lang po dito
follow back ko po kayo
salamat mga master
New Update Vmes para sa mga http custom user 1day only for config testing.
1 day lang muna testing config.
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