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[Monk G]

If 20 g of ethanol (formula mass 46) and 30 g of water (formula mass 18) are mixed together, the mole fraction of ethanol in this mixture is.
A. 0.261
B. 0.207
C. 0.739
D. 0.793

 

[0x0ffset]

To find the mole fraction of ethanol in the mixture, you need to calculate the moles of ethanol and water first.

1. Moles of Ethanol (C2H5OH):
   • Given mass of ethanol = 20 g
   • Formula mass of ethanol (C2H5OH) = 46 g/mol
   • Moles of ethanol = (Given mass of ethanol) / (Formula mass of ethanol) = 20 g / 46 g/mol = 0.4348 moles
2. Moles of Water (H2O):
   • Given mass of water = 30 g
   • Formula mass of water (H2O) = 18 g/mol
   • Moles of water = (Given mass of water) / (Formula mass of water) = 30 g / 18 g/mol = 1.6667 moles

Now, calculate the mole fraction of ethanol:

Mole fraction of ethanol (X_ethanol) = (Moles of ethanol) / (Total moles in the mixture) = (0.4348 moles) / (0.4348 moles + 1.6667 moles) = 0.4348 / 2.1015

Now, calculate this fraction:

X_ethanol ≈ 0.207

So, the mole fraction of ethanol in the mixture is approximately 0.207.

The correct answer is B. 0.207.

 

[🤖]

To find the mole fraction of ethanol in the mixture, we first need to calculate the number of moles of ethanol and water.

Number of moles of ethanol = mass of ethanol / molar mass of ethanol
Number of moles of ethanol = 20 g / 46 g/mol
Number of moles of ethanol = 0.435 moles

Number of moles of water = mass of water / molar mass of water
Number of moles of water = 30 g / 18 g/mol
Number of moles of water = 1.667 moles

Next, we need to calculate the total number of moles in the mixture.

Total number of moles = moles of ethanol + moles of water
Total number of moles = 0.435 + 1.667
Total number of moles = 2.102 moles

Finally, we can calculate the mole fraction of ethanol.

Mole fraction of ethanol = moles of ethanol / total moles
Mole fraction of ethanol = 0.435 moles / 2.102 moles
Mole fraction of ethanol = 0.207

Therefore, the mole fraction of ethanol in the mixture is approximately 0.207. Therefore, the correct answer is B. 0.207.