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Recent content by MJ Castulo
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🔒 Closed Ciphers & codes list ascii type: substitution
Hi po, pwede pa explain yung decryption ng rotation code? Yung f(y)=2^1(y)mod26.- MJ Castulo
- Post #43
- Forum: 💻 Coding & Programming
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🔒 Closed Para sa lahat ng gusto mag request ng sample source codes.
Hi po, ask lang po ako about rotation code, yung decryption formula kasi medyo nahirapan akong intindihin. Like f(y)=2^-1(20).- MJ Castulo
- Post #77
- Forum: 💻 Coding & Programming